Ask Question
Yesterday, 23:59

Calculate the [oh-] in a solution with a ph of 12.52.

+3
Answers (1)
  1. Today, 00:21
    0
    PH + pOH = 14

    12.52 + pOH = 14

    pOH = 14 - 12.52

    pOH = 1.48

    [OH⁻] = 10^ - pOH

    [OH⁻] = 10 ^ - 1.48

    [OH⁻] = 0.033 M
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Calculate the [oh-] in a solution with a ph of 12.52. ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers