Write the equilibrium constant: Pb3 (PO4) 2 (s) = 3Pb2 + (aq) +

2PO2 (aq)

Question

Avery Conway

Chemistry

19 February, 03:28

Write the equilibrium constant: Pb3 (PO4) 2 (s) = 3Pb2 + (aq) +

2PO2 (aq)

+1

Answers (1)

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Spud · Answer 1

Kc = [Pb²⁺]³.[PO₄³⁻]²

Explanation:

Let's consider the following reaction at equilibrium.

Pb₃ (PO₄) ₂ (s) ⇄ 3 Pb²⁺ (aq) + 2 PO₄³⁻ (aq)

The concentration equilibrium constant is the product of the concentrations of the products raised to their stoichiometric coefficients divided by the product of the concentrations of the reactants raised to their stoichiometric coefficients. It only includes gases and aqueous species.

Kc = [Pb²⁺]³.[PO₄³⁻]²

This equilibrium constant is known as the solubility product of Pb₃ (PO₄) ₂.

Write the equilibrium constant: Pb3 (PO4) 2 (s) = 3Pb2 + (aq) +2PO2 (aq)

Write the equilibrium constant: Pb3 (PO4) 2 (s) = 3Pb2 + (aq) +

2PO2 (aq)