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28 August, 14:01

How much heat, in joules and in calories, is required to heat 28.4g ice cube from - 23 to - 1

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  1. 28 August, 14:18
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    Given:

    Mass of ice cube, m = 28.4 g

    Initial temperature, T1 = - 23 C

    Final temperature, T2 = - 1 C

    To determine:

    Heat required to raise the temperature from T1 to T2

    Explanation:

    Heat required (Q) is given as:

    Q = mcΔT = mc (T2-T1)

    where c = specific of ice (water) = 4.182 J/g C

    Q = 28.4 * 4.182 * (-1 - (-23)) = 2612.9 J

    Since 1 J = 0.239 cal

    The corresponding Q = 0.239*2612.9 = 624.48 cal

    Ans: Q = 2612.9 J

    Q = 624.4 cal
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