How many grams of sucrose, C12H22O11, are in a 94.2 mL sample of a 2.6 M sucrose solution

First, convert molarity to moles by multiplying it by the volume in liters.

(2.6M) (.0942L) =.245mol sucrose

Then multiply it by the molar mass:

(.245mol sucrose) (342.3g/mol) = 83.8g sucrose