Students working in lab accidentally spilled 17 l of 3.0 m h2so4 solution. they find a large container of acid neutralizer that contains baking soda, nahco3. how many grams of baking soda will be needed to neutralize the sulfuric acid spill? do not include a unit in your answer or it will be counted wrong. use correct significant figures

Question

Mariah Mckinney

Chemistry

15 April, 05:09

Students working in lab accidentally spilled 17 l of 3.0 m h2so4 solution. they find a large container of acid neutralizer that contains baking soda, nahco3. how many grams of baking soda will be needed to neutralize the sulfuric acid spill? do not include a unit in your answer or it will be counted wrong. use correct significant figures

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Kara Suarez · Answer 1

Answer is: 8568.71 of baking soda.

Balanced chemical reaction: H₂SO₄ + 2NaHCO₃ → Na₂SO₄ + 2CO₂ + 2H₂O.

V (H₂SO₄) = 17 L; volume of the sulfuric acid.

c (H₂SO₄) = 3.0 M, molarity of sulfuric acid.

n (H₂SO₄) = V (H₂SO₄) · c (H₂SO₄).

n (H₂SO₄) = 17 L · 3 mol/L.

n (H₂SO₄) = 51 mol; amount of sulfuric acid.

From balanced chemical reaction: n (H₂SO₄) : n (NaHCO₃) = 1 : 2.

n (NaHCO₃) = 2 · 51 mol.

n (NaHCO₃) = 102 mol, amount of baking soda.

m (NaHCO₃) = n (NaHCO₃) · M (NaHCO₃).

m (NaHCO₃) = 102 mol · 84.007 g/mol.

m (NaHCO₃) = 8568.714 g; mass of baking soda.