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22 May, 20:39

11. The Ka for benzoic acid is 6.5 * 10-5. Calculate the pH of a 0.10 M benzoic acid solution.

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  1. 22 May, 21:01
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    2.6

    Explanation:

    Benzoic acid is a weak acid that dissociates according to the following equation.

    C₆H₅COOH (aq) ⇄ C₆H₅COO⁻ (aq) + H⁺ (aq)

    We can calculate the equilibrium concentration of H⁺ using the following expression.

    [H⁺] = √ (Ka * Ca)

    where,

    Ka is the acid dissociation constant

    Ca is the initial concentration of the acid

    [H⁺] = √ (6.5 * 10⁻⁵ * 0.10) = 2.5 * 10⁻³

    The pH is

    pH = - log [H⁺] = - log 2.5 * 10⁻³ = 2.6
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