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18 March, 01:11

The same reaction is begun with an initial concentration of 0.05 M O3 and 0.02 M NO. Under these conditions, the reaction reaches completion in 8 seconds. What is the initial rate of this reaction with respect to O3?

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  1. 18 March, 01:35
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    The balanced equation of the reaction is:

    O3 (g) + NO (g) → O2 (g) + NO2 (g)

    Then the ratios of reaction is 1 mol O3 : 1 mol NO : 1 mol O2 : 1 mol NO2

    If you have initially 0.05 M of O3 and 0.02 M of NO, the reaction will end when all the NO is consumed.

    The by the stoichiometry 0.02 mol of O3 will be consumed in 8 seconds.

    And the rate of reaction is change in concetration divided by the time.

    The change in concentration in O3 is 0.02 M

    Then, the rate respect O3 is 0.02 M / 8 seconds = 0.0025 M/s
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