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1 June, 00:10

A chemist prepares a solution of nickel (II) chloride (NiCly) by measuring out 61.3 umol of nickel (II) chloride into a 200 ml volumetric flask and filling the flask to the mark with water. Calculate the concentration in umol/L of the chemist's nickel (II) chloride solution. Round your answer to 3 significant digits. x 5? Explanation Check 2009 Mew Econ Aires Reserved. Terms of Use

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  1. 1 June, 00:15
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    The concentration of nickel (II) chloride in μmol/l will be 307 μmol/l

    Explanation:

    If in 200 ml you have 61.3 μmol, then, in 1000 ml (1 l) you will have:

    1000 ml * (61.3 μmol / 200 ml) = 306.5 μmol.

    Rounded to 3 significant digits: 307 μmol.

    The concentration will be 307 μmol/l or 307 μM.
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