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20 August, 16:38

What mass of oxygen gas is produced by the reaction of 3.8 g of ammonium perchlorate?

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  1. 20 August, 16:58
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    There is 1.29 grams of O2 produced.

    Explanation:

    Step 1: Data given

    Mass of ammonium perchlorate 3.8 grams

    Molar mass of ammonium perchlorate = 117.49 g/mol

    Step 2: The balanced equation

    4NH4ClO4 → 5O2 + 6H2O + 2N2 + 4HCl

    Step 3: Calculate moles of NH4ClO4

    Moles NH4ClO4 = mass NH4ClO4 / molar mass NH4ClO4

    Moles NH4ClO4 = 3.80 grams / 117.49 g/mol

    Moles NH4ClO4 = 0.0323 moles

    Step 4: Calculate moles of O2

    For 4 moles of ammonium perchlorate consumed, we produce 5 moles O2, 6 moles H2O, 2 moles N2 and 4 moles HCl

    For 0.0323 moles NH4ClO4 we'll have 5/4 * 0.0323 = 0.040375 moles of O2

    Step 5: Calculate mass of O2

    Mass O2 = moles O2 * molar mass O2

    Mass O2 = 0.040375 moles * 32 g/mol

    Mass O2 = 1.29 grams

    There is 1.29 grams of O2 produced.
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