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7 April, 15:04

If a gas's [kelvin] temperature doubles and it's volume then remains the same, then what happens to it's pressure?

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  1. 7 April, 15:19
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    The final pressure will double i. e it will be twice the initial pressure

    Explanation:

    T1 = T

    T2 = 2T (twice the original T)

    P1 = P

    P2 = ?

    Since the volume is constant,

    P1 / T1 = P2 / T2

    P / T = P2 / 2T

    Cross multiply

    T x P2 = 2T x P

    Divide both side by T

    P2 = (2T x P) / T

    P2 = 2P

    Therefore, the final pressure will double i. e it will be twice the initial pressure
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