For the reaction

CH3OH + O2 → HCO2H + H2O,

what is the maximum amount of HCO2H

which could be formed from 8.02 mol of

CH3OH and 15.49 mol of O2?

368.92 g of HCOOH could be formed.

Explanation:

First we have to write the balanced equation as,

CH₃OH + O₂ → HCOOH + H₂O

Here the question said that 8.02 mol of CH₃OH and 15.49 mol of O₂.

In the above reaction methanol and oxygen is used in 1:1 ratio, but the moles are lesser in case of methanol, so CH₃OH is the limiting reagent.

Now by making use of 8.02 moles of methanol, we can produce 8.02 mol of HCOOH.

Molar mass of HCOOH is 46 g/mol.

So mass of HCOOH formed is moles * molar mass of HCOOH.

8.02 moles * 46 g/mol = 368.92 g of HCOOH could be formed.