How much heat is added if. 7892g of water is increased in temperature by. 039 degrees C?

=0.1293 J

Explanation:

The heat increase is the change in energy for the water ΔH.

ΔH=MC∅ where M is mass, C is the specific heat capacity for water and ∅ is the change in temperature.

M=0.7892g

C (for water) = 4.2 J/g°C

∅=0.039 °C

ΔH=0.7892g*4.2 J/g°C*0.039°C

=0.1293 J

The amount of heat energy added to cause the 0.039°C temperature increase is 0.1293 Joules.