A measured sample of Argon gas has a volume of 20.0L at a pressure of 660 mmHg. What is the final volume if the pressure is decreased to 550 mmHg?

17L

240L

5.5L

24L

The answer to your problem is: V2 = 24.0 L

Explanation:

To solve this problem we need to use the Boyle's law that says:

P1V1 = P2V2

dа ta:

P1 = 660 mmHg

P2 = 550 mmHg

V1 = 20 l

V2 = ? l

Now, we need to clear V2 from the equation

V2 = P1V1/P2

Substitution

V2 = 660 mmHg x 20 l / 550 mmHg

V2 = 13200 / 550

Result V2 = 24.0 l