An aqueous potassium iodate (KIO3) solution is made by dissolving 553 grams of KIO3 in sufficient water so that the final volume of the solution is 2.10 L.

Calculate the molarity of the KIO3 solution.

Answer: 1.229M

Explanation:

To get the molarity of KIO3, we must first calculate the number of mole of KIO3 that dissolves in 2.10 L of the solution

This can be achieved by doing the following:

MM of KIO3 = 39 + 127 + (3 x 16) = 214g/mol

Mass conc of KIO3 = 553g

Number of mole = Mass conc. / molar Mass

Number of mole = 553g/214

Number of mole = 2.58moles

We can solve for the molarity by using:

Molarity = number of mole / Volume

Molarity = 2.58/2.1

Molarity = 1.229M

Therefore, the molarity of KIO3 solution is 1.229M

M KIO3 = 1.254 mol/L

Explanation:

molarity (M) [=] mol/L

∴ w KIO3 = 553 g

∴ mm KIO3 = 214.001 g/mol

∴ volumen sln = 2.10 L

⇒ mol KIO3 = (553 g) * (mol/210.001 g) = 2.633 mol

⇒ M KIO3 = (2.633 mol KIO3 / (2.10 L sln)

⇒ M KIO3 = 1.254 mol/L