If 6.24 L of a gas at 45.0°C is cooled until its volume decreases to 5.17 L, what is the temperature of the gas in degrees Celsius

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Olson

Chemistry

11 March, 19:04

If 6.24 L of a gas at 45.0°C is cooled until its volume decreases to 5.17 L, what is the temperature of the gas in degrees Celsius

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Levi Long · Answer 1

Charles' Law states that as temperature decreases, the volume of a gas decreases with it. As temperature increases, the volume of a gas increases as well. Thus, we say that the temperature and the volume of a gas are directly proportional. The equation that we use to solve this problem reads as follows:

V1/T1 = V2/T2

Remember that T1 will always be the temperature that you are trying to calculate, so:

6.24L (T1) = 5.17L (45.0 C)

6.24 (T1) = 232.65

Therefore, T1 = 37.22 C