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31 March, 09:12

A bomb calorimeter has a heat capacity of 2.18 kJ/K. When a 0.176g sample of gas with a molar mass of 28.0 g/mol was burned in this calorimeter, the temperature increases by 2.12 K. Calculate the heat of combustion for 1 mol of this gas. - 1.29 x 10^2 kJ - 4.62 kJ - 2.63 x 10 kJ - 0.0291 kJ - 7.35 x 10^2 kJ

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  1. 31 March, 09:33
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    Heat of combustion = -7.35 * 10² kJ

    Explanation:

    Step 1: Data given

    Mass = 0.176 grams

    Molar mass = 28.0 g/mol

    Temperature increase 2.12 K

    A bomb calorimeter has a heat capacity of 2.18 kJ/K

    Step 2: Calculate heat of combustion

    Energy released = mass * heat capacity * change in temperature

    Q = c*∆T

    Q = 2.18 kJ/K*2.12 K = 4.62 kJ released

    Heat of combustion = (energy released) / (mole of substance)

    Moles of gas = (0.176 g) / (28.0 g/mol) = 0.00629 moles

    Heat of combustion = (energy released) / (mole of substance)

    Heat of combustion = (4.62 kJ) / (0.00629 moles) = 7.35 * 10² kJ

    Heat of combustion = -7.35 * 10² kJ (negative because heat is lost)
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