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18 May, 09:56

A sample of 0.020 mole of oxygen gas is confined at 227°C and 0.50 atmospheres. What would be the pressure of this sample at 27°C and the same volume?

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  1. 18 May, 10:11
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    Answer:-

    0.3 atm

    Explanation:-

    Number of moles n = 0.020 mol

    Pressure P 1 = 0.5 atm

    Temperature T 1 = 227 C + 273 = 500 K

    We know the value of universal Gas constant R = 0.082 L atm K-1 mol-1

    We use the relation PV = nRT

    V = nRT / P

    Plugging in the values

    V = 0.020 mol x (0.082 L atm K-1 mol-1) x 500 K / (0.5 atm)

    = 1.64 L

    Now the new temperature T 2 = 27 C + 273 = 300 K.

    Volume is same = 1.64 L

    Number of moles n is same = 0.020 mol

    Once again we use the relation

    PV = nRT

    New Pressure P = nRT / V

    = 0.020 x 0.082 L atm K-1 mol-1 x 300 K / 1.64 L

    = 0.3 atm
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