If you have 5.2 moles of Na and excess CI2 how many moles of NaCI will be produced 2Na+CI2->2NaCI

10.4 moles NaCI

2.6 moles NaCI

5.2 moles NaCI

2 moles NaCI

Question

Jacklyn

Chemistry

15 January, 14:27

If you have 5.2 moles of Na and excess CI2 how many moles of NaCI will be produced 2Na+CI2->2NaCI

10.4 moles NaCI

2.6 moles NaCI

5.2 moles NaCI

2 moles NaCI

+3

Answers (1)

Know the Answer?

Zavier Huffman · Answer 1

5.2moles of NaCl

Explanation:

The equation for the reaction is:

2Na + Cl2 - > 2NaCl

From the equation,

2moles of Na produced 2moles of NaCl.

Therefore, 5.2moles of Na will also produce 5.2moles of NaCl

If you have 5.2 moles of Na and excess CI2 how many moles of NaCI will be produced 2Na+CI2->2NaCI10.4 moles NaCI2.6 moles NaCI5.2 moles NaCI2 moles NaCI

If you have 5.2 moles of Na and excess CI2 how many moles of NaCI will be produced 2Na+CI2->2NaCI

10.4 moles NaCI

2.6 moles NaCI

5.2 moles NaCI

2 moles NaCI