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21 February, 14:17

How many grams of NaNo3 are required to saturate 200 grams of water at 10 degrees Celsius

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  1. 21 February, 14:24
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    162.0 g.

    Explanation:

    The solubility is the maximum amount of solute dissolved in a given amount of solvent to form saturated solution.

    The solubility of NaNO₃ in 100.0 g of water at 10.0°C is 81.0 g / 100 g water.

    Using cross multiplication:

    81.0 g of NaNO₃ form saturated solution at 10.0°C in → 100.0 g of water.

    ? g of NaNO₃ form saturated solution at 10.0°C in → 200.0 g of water.

    ∴ The grams of NaNO₃ form saturated solution at 10.0°C in 200.0 g of water = (81.0 g) (200.0 g) / (100.0 g) = 162.0 g.
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