What is the approximate tangential speed of an object orbiting Earth with a radius of 1.8 * 108 m and a period of 2.2 * 104 s?

7.7 * 10^-4 m/s

5.1 * 10^4 m/s

7.7 * 10^4 m/s

5.1 * 10^5 m/s

If the period is 2.2 x 104 s, then the rotational speed is:

1 / 2.2x104 = 4.55x10-5 rad/s

We can solve for the tangential speed using the formula:

v = ωr

where ω is the rotational speed

v is the linear or tangential speed

r is the radius

So,

v = 4.55x10-5 (1.8x108)

v = 5.1 x 104 m/s