Calculate the volume in liters of a potassium iodide solution that contains of potassium iodide. Be sure your answer has the correct number of significant digits.

23.8 L

Explanation:

There is some info missing. I think this is the original question.

Calculate the volume in liters of a 0.0380M potassium iodide solution that contains 150 g of potassium iodide. Be sure your answer has the correct number of significant digits.

The molar mass of potassium iodide is 166.00 g/mol. The moles corresponding to 150 grams are:

150 g * (1 mol/166.00 g) = 0.904 mol

0.904 moles of potassium iodide are contained in an unknown volume of a 0.0380 mol/L potassium iodide solution. The volume is:

0.904 mol * (1 L/0.0380 mol) = 23.8 L