Given the balanced equation that follows, how many milliliters of carbon dioxide gas at STP are

produced from the decomposition of 3.67 g of ferric carbonate?

Fe2 (CO3) 3 - 'Fe2O3 + 3C02

1,000 mL = 1 liter

Molar mass of ferric carbonate (Fe2 (CO3) 3) = 291.7 g/mol

870 mL

Explanation:

Given dа ta:

Mass of ferric carbonate = 3.67 g

Molar mass of ferric carbonate = 291.7 g/mol

Volume of CO₂ produced = ?

Solution:

Chemical equation:

Fe₂ (CO₃) ₃ → Fe₂O₃ + 3CO₂

Number of moles of ferric carbonate:

Number of moles = mass / molar mass

Number of moles = 3.67 g/291.7 g/mol

Number of moles = 0.013 mol

Now we will compare the moles of ferric carbonate with carbon dioxide.

Fe₂ (CO₃) ₃ : CO₂

1 : 3

0.013 : 3*0.013 = 0.039 mol

Litters of carbon dioxide at STP:

PV = nRT

V = nRT/P

V = 0.039 mol * 0.0821 atm. L/mol. K * 273 K / 1 atm

V = 0.87 L

Litter to mL:

1000 mL = 1 L

0.87L*1000 mL/1 L = 870 mL