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17 October, 11:10

A sample of gas at 301 Kelvin and 1.5 atmospheres has a density of 3.90 g/L. What is the molar mass of this gas? Show all of the work used to solve this problem.

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  1. 17 October, 11:33
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    PV = nRTP is pressure, V is volume in L, n is number of moles, R is the gas constant, and T is temperature in K

    (1.5 atm) (1 L) = (n) (.08206) (301K)

    n =.06 moles in one liter

    If there are 3.9 grams in. 06 moles then

    1/.06 x 3.9 = 64.2 grams per mol
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