Ask Question
29 September, 07:22

15.434 g of kcl (m. m 74.55 g/mol) is dissolved in water up t a total volume of 500.0 mL. the density of this solution is 1.02 g/mL. what is the concentration of he solution in molality

+4
Answers (1)
  1. 29 September, 07:26
    0
    0.412mol/Kg

    Explanation:

    First, let us fine the number of mole of KCl ... This is illustrated below

    Mass of KCl = 15.434g

    Molar Mass of KCl = 74.55 g/mol

    Number of mole = Mass / Molar Mass

    Number of mole KCl = 15.434/74.55 = 0.21mole

    Now, let us calculate the mass of the water in kg. This can be achieved by doing the following:

    Density = 1.02 g/mL

    Volume = 500mL

    Mass = ?

    Mass = Density x volume

    Mass of water = 1.02 x 500 = 510g

    Converting 510g to kg, we have: 510/1000 = 0.51kg

    Now we calculate for the molality as follows:

    Mole of the solute = 0.21mole

    Mass of the solvent = 0.51Kg

    Molality = mole of solute / mass of solvent

    Molality = 0.21/0.51

    Molality = 0.412mol/Kg
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “15.434 g of kcl (m. m 74.55 g/mol) is dissolved in water up t a total volume of 500.0 mL. the density of this solution is 1.02 g/mL. what ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers