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21 August, 23:54

Calculate the molality of the solution. (assume a density of 1.08 g/ml for the solution.) an aqueous nacl solution is made using 140 g of nacl diluted to a total solution volume of 1.20

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  1. 22 August, 00:16
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    molality is moles solute / kg of solvent

    moles of NaCl = mass / molar mass

    molar mass NaCl = 58.44 g/mol

    moles NaCl = 140 g / 58.44 g/mol = 2.40 mol NaCl

    The total volume of the solution is 1.2L or 1200 ml

    The density of the solution is 1.08 g/ml

    Therefore the total mass of the solution is 1.08 g/ml x 1200 ml

    = 1296 g

    But there are140 g of NaCl in this solution

    So mass H2O = 1296 g - 140 g

    = 1156 g

    = 1.156 kg

    molality = moles solute / kg solvent

    = 2.40 mol / 1.156 kg

    = 2.08 molal
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