How do i use the factor-label method to calculate the number of grams of kmno4 that you would need to make 100 ml of a 0.0045 m potassium permanganate solution?

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James Spears

Chemistry

5 December, 09:34

How do i use the factor-label method to calculate the number of grams of kmno4 that you would need to make 100 ml of a 0.0045 m potassium permanganate solution?

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Korbin Haas · Answer 1

Factor-label, also known as dimensional analysis, describes a technique to convert one quantity - a length, mass or anything else for that matter - to another quantity.

V (KMnO₄) = 100 ml.

c (KMnO₄) = 0,0045 mol/l = 0,0000045 mol/ml.

m (KMnO₄) = V (KMnO₄) · c (KMnO₄) · M (KMnO₄).

m (KMnO₄) = 100 ml/1 · 0,0000045 mol/ml · 158 g/mol.

m (KMnO₄) = 0,0711 g.