What is the de Broglie wavelength of a proton with a velocity of 2.5e6

m/s?

The deBroglie wavelength of a proton with a velocity of 2.5e6 is λ=1.654*10^24 m2 kg

Explanation:

We have the formula,

λ = h/mv

λ = h/p (p=mv) assume mass be 1

λ = 6.62607004 * 10-34 m2 kg / s

/2.5*1.602176634*10^-19*10^6

λ = 6.62607004 * 10-34 m2 kg / s / 4.005425

*10^-13

λ=1.654*10^24 m2 kg

The deBroglie wavelength of a proton with a velocity of 2.5e6 is λ=1.654*10^24 m2 kg