T he thermochemical equation for the reaction between hydrazine, N2H4, and dinitrogen tetroxide is given as: 2N2H4 (2) N204 (1) 3N2 (g) + 4H20 (g), AHO-1049 kJ What is the corresponding thermochemical equation for this reaction when 6 mol of nitrogen are formed?

4N2H4 (2) + 2N204 (1) - -> 6N2 (g) + 8H20 (g), AHO-2098 kJ

Explanation:

2N2H4 (2) + N204 (1) - -> 3N2 (g) + 4H20 (g), AHO-1049 kJ

when 6 mol of nitrogen are formed?

The ratio of Nitrogen in the previous therrmochemical equation to when 6 mol f nitrogen are formed is 2; 6/3 = 2.

So to get the new thermoochemical equation, multiply all parameters in the given equation by 2.

We have;

4N2H4 (2) + 2N204 (1) - -> 6N2 (g) + 8H20 (g), AHO-2098 kJ