Given a fixed amount of gas held at constant pressure, calculate the volume (in L) it would occupy if a 3.50 L sample were cooled from 90.0oC to 30.0oC.

V₂ = 2.91 L

Explanation:

Given dа ta:

Initial volume = 3.50 L

Initial temperature = 90.0°C (90+273 = 363 K)

Final temperature = 30.0 °C (30 + 273 = 303 K)

Final volume = ?

Solution:

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume

T₂ = Final temperature

V₁/T₁ = V₂/T₂

3.50 L / 363 K) = V₂ / 303 K)

V₂ = 0.0096 L/K * 303 K

V₂ = 2.91 L