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Yesterday, 01:30

A 100 g sample of an unknown liquid absorbs 2000 j of heat energy, raising the liquid's temperature from 50 ◦ c to 70 ◦

c. what is the specific heat capacity of this liquid? no phase change took place.

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  1. Yesterday, 01:59
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    Since there is no phase change, we can use the heat equation,

    Q = mcΔT

    where Q is the amount of energy transferred (J), m is the mass of the substance (kg), c is the specific heat (J kg⁻¹ °C⁻¹) and ΔT is the temperature difference (°C).

    Q = 2000 J

    m = 100 g = 0.1 kg

    c = ?

    ΔT = (70 °C - 50 °C) = 20 °C

    By applying the formula,

    2000 J = 0.1 kg x c x 20 °C

    c = 2000 J / (0.1 kg x 20 °C)

    c = 1000 J kg⁻¹ °C⁻¹

    Hence, the specific heat capacity of the liquid is 1000 J kg⁻¹ °C⁻¹.
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