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27 December, 02:42

A 50°C solution has a pH of 3.30. At this temperature, Kw = 5.48 x 10 9. What is the pOH of the solution?

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  1. 27 December, 02:57
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    9.93

    Explanation:

    Your value for Kw is incorrect. The correct value is 5.48 * 10^-14.

    pH + pOH = pKw

    3.30 + pOH = - log (5.84 * 10^-14) = 13.23

    pOH = 13.23 - 3.30 = 9.93

    The pOH of the solution is 9.93.
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