Ask Question
3 August, 00:53

How many grams of the molecule glucose C6H12O6 would be required to make 1 L of a 0.5 M solution of the molecule?

+4
Answers (1)
  1. 3 August, 01:21
    0
    90g

    Explanation:

    We need to find the molar mass of C6H12O6. This is done below:

    MM of C6H12O6 = (12x6) + (12x1) + (6x16) = 72 + 12 + 96 = 180g/mol

    From the question, we obtained:

    Volume = 1L

    Molarity = 0.5M

    Number of mole = Molarity x Volume

    Number of mole = 0.5 x 1 = 0.5mol

    Mass conc of C6H12O6 = number of mole x MM = 0.5 x 180 = 90g
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “How many grams of the molecule glucose C6H12O6 would be required to make 1 L of a 0.5 M solution of the molecule? ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers