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28 December, 21:06

How many moles of water will be generated during the combustion of 0.38 moles of methyl alcohol (CH3OH) ? 2CH3OH + 3O2 2CO2 + 4H2O

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  1. 28 December, 21:20
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    You already got the balanced equation. So the ratio of mole number is the ratio of the coefficient. Then the ratio of methyl alcohol and water is 2:4=1:2. The water generated is 0.38*2=0.76 mol.
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