Ask Question
28 December, 00:10

What is the pressure of 0.500mol of gas at 12.2 L and 273K

+2
Answers (1)
  1. 28 December, 00:36
    0
    P = 0.92 atm

    Explanation:

    Given dа ta:

    Pressure of gas = ?

    Number of moles = 0.500 mol

    Volume of gas = 12.2 L

    Temperature of gas = 273 K

    Solution:

    The given problem will be solve by using general gas equation,

    PV = nRT

    P = Pressure

    V = volume

    n = number of moles

    R = general gas constant = 0.0821 atm. L / mol. K

    T = temperature in kelvin

    Now we will put the values.

    P = nRT/v

    P = 0.500 mol * 0.0821 atm. L / mol. K * 273 K / 12.2 L

    P = 11.2 / 12.2 L

    P = 0.92 atm
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “What is the pressure of 0.500mol of gas at 12.2 L and 273K ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers