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29 August, 10:05

25 mL of Ca (OH) 2 is titrated with 17.8 mL of 0.1 M HCl. What is the concentration of Ca (OH) 2?

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  1. 29 August, 11:14
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    To determine the concentration of the calcium hydroxide, we need to relate the acid used by using the chemical reaction involved. The chemical reaction would be

    Ca (OH) 2 + 2HCl = CaCl2 + 2H2O

    We calculate as follows:

    Mole HCl = 0.1 M (.0178 L) = 1.78x10^-3 mol HCl

    Mole Ca (OH) 2 reacted = 1.78x10^-3 mol HCl (1 mol Ca (OH) 2 / 2 mol HCl) = 8.4x10^-4 mol

    Conc'n Ca (OH) 2 = 8.4x10^-4 mol /.025 L = 0.04 M
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