Ask Question
26 February, 14:24

If the compound contains 35.06 % cl by mass, what is the identity of the metal?

+1
Answers (1)
  1. 26 February, 14:31
    0
    Answer is: identity of the metal is gold (Au).

    ω (Cl) = 35.06% : 100%.

    ω (Cl) = 0.3506; mass percentage of chlorine.

    If we take 100 grams of the compound:

    m (Cl) = ω (Cl) · m (compound).

    ω (Cl) = 0.3506 · 100 g.

    ω (Cl) = 35.06 g.

    n (Cl) = m (Cl) : M (Cl).

    n (Cl) = 35.06 g : 35.45 g/mol.

    n (Cl) = 0.99 mol; amount of substance.

    In molecule MCl₃: n (M) : n (Cl) = 1 : 3.

    n (M) = 0.33 mol; amount of unknown metal.

    M (M) = m (M) : n (M).

    M (M) = (100 g - 35.06 g) : 0.33 mol.

    M (M) = 196.8 g/mol; molar mass of the gold.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “If the compound contains 35.06 % cl by mass, what is the identity of the metal? ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers