A molecule contains 24.36g of N and 62.64 g of Ag. What is its empirical formula

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Ciara

Chemistry

21 August, 20:54

A molecule contains 24.36g of N and 62.64 g of Ag. What is its empirical formula

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Hayden · Answer 1

Answer is: empirical formula is AgN₃.

m (N) = 24,36 g.

n (N) = m (N) : M (N).

n (N) = 24,36 g : 14 g/mol.

n (N) = 1,74 mol.

m (Ag) = 62,64 g.

n (Ag) = m (Ag) : M (Ag).

n (Ag) = 62,64 g : 107,87 g/mol.

n (Ag) = 0,58 mol.

n (N). n (Ag) = 1,74 mol : 0,58 mol / : 0,58.

n (N). n (Ag) = 3 : 1.