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13 July, 10:12

How many milliliters of a 0.40 m solution of hydrochloric acid are necessary to neutralize 25 ml of a 0.20 m sodium hydroxide solution?

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  1. 13 July, 10:35
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    12.5 mL of HCl

    Explanation:

    The balanced chemical equation for the neutralization reaction is as follows

    NaOH + HCl - > NaCl + H2O

    Molar ratio of NaOH to HCl is 1:1

    For neutralization to happen the number of NaOH moles is equal to the number of HCl moles

    Number of NaOH moles reacted - 0.20 mol/L x 0.025 L = 0.005 mol

    Therefore number of HCl moles reacted - 0.005 mol

    Concentration of HCl is 0.40 mol/L

    Concentration = number of moles / volume

    Rearranging the equation

    Volume = number of moles / concentration

    Volume = 0.005 mol / 0.40 mol/L

    = 0.0125 L

    Volume of HCl added is 12.5 mL
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