Which conditions apply at ph = 7.0? [h+] > [oh-]; the solution is acidic [h+] < [oh-]; the solution is basic [h+] = [oh-] = 0m [h+] = [oh-] = 1 * 10-7m?

[H + ] = [OH] = 1 * 10 - 7 M

Answer : The correct answer is " [H⁺] = [OH⁻] = 1 x 10⁻⁷ M

When pH is 7, the solution is neutral means neither acidic nor basic.

So, [h+] > [oh-]; the solution is acidic and [h+] < [oh-] the solution is basic options cancels out.

If concentration of H + and OH - is checked:

Step 1 : To find concentration of H + using pH formula

the formula of pH = - log [H⁺]

Where,[H+] = concentration of Hydrogen ions.

Given : pH = 7

Plugging values of pH in formula

7 = - log [H⁺]

To remove log, antilog of 7 is taken

10⁻⁷ = [H⁺]

[H⁺] = 1 x 10⁻⁷ M

Step 2 : Concentration of OH⁻ = >

The relation between pH and pOH = > pH + pOH = 14

pOH = 14-pH = 14 - 7 = 7

pOH = 7

Relation between pOH and [OH⁻] is = > pOH = - log [OH⁻]

Plugging value of pOH in formula

7 = - log [OH⁻]

[OH⁻] = 10⁻⁷ = 1 x 10⁻⁷ M

Hence concentration of [OH⁻ ]and [H⁺ ] = 1 x 10⁻⁷ M