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6 September, 00:13

How many liters of nitrogen gas are needed to make 25 mol of nitrogen trifluoride

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  1. 6 September, 00:39
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    The reaction between N₂ and F₂ gives Nitrogen trifluoride as the product. The balanced equation is;

    N₂ + 3F₂ → 2NF₃

    The stoichiometric ratio between N₂ and NF₃ is 1 : 2

    Hence,

    moles of N₂ / moles of F₂ = 1 / 2

    moles of N₂ / 25 mol = 0.5

    moles of N₂ = 0.5 x 25 mol = 12.5 mol

    Hence N₂ moles needed = 12.5 mol

    At STP (273 K and 1 atm) 1 mol of gas = 22.4 L

    Hence needed N₂ volume = 22.4 L mol⁻¹ x 12.5 mol

    = 280 L
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