One bit of evidence that the present theory of atomic structure is "correct" lies in the magnetic properties of matter. Atoms with unpaired electrons are attracted by magnetic fields and thus are said to exhibit paramagnetism. The degree to which this effect is observed is directly related to the number of unpaired electrons present in the atom. On the basis of the electron orbital diagrams for the following elements, indicate which atoms would be expected to be paramagnetic, and tell how many unpaired electrons each atom contains. a. phosphorus, Z = 15b. iodine, Z = 53c. germanium, Z = 32

Question

Guest

Chemistry

7 August, 12:10

One bit of evidence that the present theory of atomic structure is "correct" lies in the magnetic properties of matter. Atoms with unpaired electrons are attracted by magnetic fields and thus are said to exhibit paramagnetism. The degree to which this effect is observed is directly related to the number of unpaired electrons present in the atom. On the basis of the electron orbital diagrams for the following elements, indicate which atoms would be expected to be paramagnetic, and tell how many unpaired electrons each atom contains. a. phosphorus, Z = 15b. iodine, Z = 53c. germanium, Z = 32

+3

Answers (1)

Know the Answer?

Miguel · Answer 1

Phosphorus atoms will be paramagnetic. Iodine atoms will be paramagnetic. Germanium atoms will also be paramagnetic.

Explanation:

Phosphorus has 3 unpaired electrons. Iodine has 1 unpaired electron. And Germanium has 2 unpaired electrons. But all these simple compound will be diamagnetic because they pair their electrons on molecular orbitals.