A solution is made from 50.0 g CCl4 and 50.0 g CHCl3. What is the mole fraction of carbon tetrachloride (CCl4) in the solution? (molar masses are CCl4 = 153.8 g/mol; CHCl3 = 119.4 g/mol)

Question

Karissa

Chemistry

20 December, 10:49

A solution is made from 50.0 g CCl4 and 50.0 g CHCl3. What is the mole fraction of carbon tetrachloride (CCl4) in the solution? (molar masses are CCl4 = 153.8 g/mol; CHCl3 = 119.4 g/mol)

+2

Answers (1)

Know the Answer?

Chase Campos · Answer 1

Moles of the molecule = mass of the molecule / molar mass.

Therefore, the moles of CCl4 = 50.0g/153.8g/mol = 0.325 mol, and the moles of CHCl3 = 50.0g/119.4g/mol = 0.419 mol.

The mole fraction of CCl4 = moles of CCl4 / (moles of CCl4 + moles of CHCl3) = 0.325 mol / (0.325mol+0.419mol) = 43.7%

The mole fraction of carbon tetrachloride in the solution is 43.7%.