Suppose you wanted to find out how many milliliters of 1.0 m agno3 are needed to provide 169.9 g of pure agno3? what is step 1 in solving the problem? calculate moles agno3 needed what is the molar mass of agno3? 169.87 g/mol how many milliliters of solution are needed?

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Mckinley Clark

Chemistry

20 August, 05:53

Suppose you wanted to find out how many milliliters of 1.0 m agno3 are needed to provide 169.9 g of pure agno3? what is step 1 in solving the problem? calculate moles agno3 needed what is the molar mass of agno3? 169.87 g/mol how many milliliters of solution are needed?

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Jabari Cantrell · Answer 1

M (AgNO₃) = 169.9 g; mass.

n (AgNO₃) = m (AgNO₃) : M (AgNO₃).

n (AgNO₃) = 169.9 g : 169.87 g/mol.

n (AgNO₃) = 1 mol; amount of silver nitrate.

c (AgNO₃) = 1 M = 1 mol/L.

V (AgNO₃) = n (AgNO₃) : c (AgNO₃).

V (AgNO₃) = 1 mol : 1 mol/L.

V (AgNO₃) = 1 L.

V (AgNO₃) = 1 L · 1000 mL/L.

V (AgNO₃) = 1000 mL; volume of silver nitrate.