Two samples of sodium chloride were decomposed into their constituent elements. one sample produced 4.65 g of sodium and 7.16 g of chlorine, and the other sample produced 7.45 g of sodium and 11.5 g of chlorine. are these results consistent with the law of constant composition? explain your answer.

Question

Aleena

Chemistry

9 June, 06:53

Two samples of sodium chloride were decomposed into their constituent elements. one sample produced 4.65 g of sodium and 7.16 g of chlorine, and the other sample produced 7.45 g of sodium and 11.5 g of chlorine. are these results consistent with the law of constant composition? explain your answer.

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Nyasia Curry · Answer 1

1) m (Na) = 4.65 g.

n (Na) = m (NA) : M (Na).

n (Na) = 4.65 g : 23 g/mol.

n (Na) = 0.202 mol.

m (Cl₂) = 7.16 g.

n (Cl₂) = 7.16 g : 70.9 g/mol.

n (Cl₂) = 0.101 mol → n (Cl) = 2 · n (Cl₂) = 0.202 mol.

In sodium chloride (NaCl) proportion of sodium and chlorine atoms are:

n (Na) : n (Cl) = 1 : 1.

In this example n (Na) : n (Cl) = 0.202 mol : 0.202 mol (1 : 1).

2) n (Na) = 7.45 g : 23 g/mol.

n (Na) = 0.324 mol.

n (Cl₂) = 11.5 g : 70.9 g/mol.

n (Cl₂) = 0.162mol → n (Cl) = 0.324 mol.

n (Na) : n (Cl) = 1 : 1; results consistent with the law of constant composition.