Ask Question
27 May, 02:38

How many potassium hydroxide (KOH) formula units are present in 6.89 mol of KOH?:

A. 4.1498 * 1024

B. 4.1498 * 1023

C. 8.299 * 1024

D. 8.299 * 1023

+2
Answers (1)
  1. 27 May, 02:41
    0
    To get the number of formula units of the compound, potassium hydroxide (KOH), we must recall that for every mole of ionic compound, the number of fomula units is 6.022 * 10^23 units, or the avogadro's number. Hence, for a 6.89 mol compound, the number of formula units is 4.1498 * 10^24 units. Answer is A.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “How many potassium hydroxide (KOH) formula units are present in 6.89 mol of KOH?: A. 4.1498 * 1024 B. 4.1498 * 1023 C. 8.299 * 1024 D. ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers