Ask Question
9 August, 11:41

Question 5 A 8.00L tank at 0.6°C is filled with 8.79g of sulfur hexafluoride gas and 19.5g of carbon dioxide gas. You can assume both gases behave as ideal gases under these conditions. Calculate the mole fraction of each gas. Be sure each of your answer entries has the correct number of significant digits.

+2
Answers (1)
  1. 9 August, 11:46
    0
    Mole fraction SF₆: 0.119

    Mole fraction CO₂: 0.881

    Explanation:

    Mole fraction: Moles of gas / Total moles

    Molar mass SF6: 146.0 g/m

    Molar mass CO2: 44.0 g/m

    Moles : mass / molar mass

    Moles SF₆ : 8.79 g / 146.0 g/m = 0.060 moles

    Moles CO₂: 19.5 g / 44.0 g/m = 0.443 moles

    Total moles: 0.060 moles + 0.443 moles = 0.503 moles

    Mole fraction SF₆: 0.060 moles/0.503 moles = 0.119

    Mole fraction CO₂: 0.443 moles/0.503 moles = 0.881

    Sum of mole fraction every gas = 1
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Question 5 A 8.00L tank at 0.6°C is filled with 8.79g of sulfur hexafluoride gas and 19.5g of carbon dioxide gas. You can assume both gases ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers