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7 May, 17:52

A calorimeter is filled with 250.0 g of water at 24.6oC. A 60.0 g sample of a metal at 100.0 oC is dropped in this calorimeter and causes the temperature to increase a total of 4.5oC. What is the specific heat of the metal (in J/g°C) ? Ignore the calorimeter in this problem

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  1. 7 May, 18:04
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    Answer : The specific heat of metal in this case will be 0.411 J / g°C

    Explanation : Specific heat can be calculated by using the formula

    Q = Cm ΔT

    where Q is heat added which is 100 here

    C is specific heat which needs to be found

    m is mass of the metal

    and ΔT is the temperature change

    on substituting we get,

    100 = x. 60. 4.05

    so, x = 0.411
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