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25 March, 14:39

What temperature would be required to keep 0.895mol of gas in a 28.6L tank at a pressure of 0.500atm?

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  1. 25 March, 14:51
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    The temperature would be 194, 8 K.

    Explanation:

    We use the formula:

    PV=nRT - -> T=PV/nR

    T = 0,500 atm x 28, 6 L / 0,895 mol x 0,082 l atm / K mol

    T = 194,8494345 K
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