How many grams of HCl would be required to make 0.3 L of a 12.0 M solution?

A. 25 g

B. 146 g

C. 131 g

D. 40 g

The molarity of a solution is the quotient obtained when number of moles is divided by volume.

molarity = n / V

Calculating for n,

n = (12) (0.3) = 3.6 moles

Then, we multiply the number of moles calculated by the molar mass of HCl which is equal to 36 g/mol.

mass = (3.6 moles) (36 g/mol) = 129.6 grams