F is going to use a mixture of two brands of italian dressing. the first brand contains 9% vinegar, and the second brand contains 14% vinegar. the chef wants to make 380 milliliters of a dressing that is 12% vinegar. how much of each brand should she use?

Question

Armani Hardy

Chemistry

23 March, 12:02

F is going to use a mixture of two brands of italian dressing. the first brand contains 9% vinegar, and the second brand contains 14% vinegar. the chef wants to make 380 milliliters of a dressing that is 12% vinegar. how much of each brand should she use?

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Answers (1)

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Emeline · Answer 1

Answer is: 152 mL of 9% vinegar and 228 mL of 14% vinegar.

ω₁ = 9% : 100% = 0.09.

ω ₂ = 14% : 100% = 0.14.

ω ₃ = 12% : 100% = 0.12.

V ₁ = ?.

V₂ = ?.

V ₃ = V₁ + V₂.

V ₃ = 380 mL.

V₁ = 380 mL - V₂.

ω ₁ · V₁ + ω₂ ·V₂ = ω₃ · V₃.

0.09 · (380 mL - V₂) + 0.14 · V₂ = 0.12 · 380 mL.

34.2 mL - 0.09V₂ + 0.14V₂ = 45.6 mL.

0.05V₂ = 11.4 mL.

V₂ = 11.4 mL : 0.05.

V₂ = 228 mL.

V₁ = 380 mL - 228 mL.

V₁ = 152 mL.